Sum converting to bar chart

If you were trying to do "count" instead, that would be easy to do, using the "distribution" parameter. Doing a "sum" is harder... does each grouping of values correspond to a page? If so, maybe the best solution is to have each of those pages store its own sum, using a combination of #set and #ask; and then query on all of those semantically-stored sums.

Yaron Koren (talk)